1.If the earth is a point mass of 6×1024 kg6 \times 10^{24}\,\text{kg}6×1024kg revolving around the sun at a distance of 1.5×108 km1.5 \times 10^8\,\text{km}1.5×108km, then the angular momentum of the earth around the sun isa.1.2×1018 kg m2/s1.2 \times 10^{18}\,\text{kg m}^2/\text{s}1.2×1018kg m2/sb.1.8×1029 kg m2/s1.8 \times 10^{29}\,\text{kg m}^2/\text{s}1.8×1029kg m2/sc.1.5×1037 kg m2/s1.5 \times 10^{37}\,\text{kg m}^2/\text{s}1.5×1037kg m2/sd.2.7×1040 kg m2/s2.7 \times 10^{40}\,\text{kg m}^2/\text{s}2.7×1040kg m2/sLogin to continueOnly logged in users canattempt or see the solution.
