1.If the solution of dydx=y3cosxx e1/y2\frac{dy}{dx} = \frac{y^3\cos\sqrt{x}}{\sqrt{x}\,e^{1/y^2}}dxdy=xe1/y2y3cosx, y(0)=1y(0)=1y(0)=1 is 1y2=loge(f(x))\frac{1}{y^2} = \log_e(f(x))y21=loge(f(x)), then f(x)=f(x) =f(x)=a.4+4sinx4 + 4\sin\sqrt{x}4+4sinxb.esinxe\sin\sqrt{x}esinxc.1−4sinx1 - 4\sin\sqrt{x}1−4sinxd.e−4sinxe - 4\sin\sqrt{x}e−4sinxLogin to continueOnly logged in users canattempt or see the solution.
