1.The Boolean expression (p∧q)⇒((r∨q)∧p)(p \wedge q) \Rightarrow ((r \vee q) \wedge p)(p∧q)⇒((r∨q)∧p) is equivalent to:a.(p∧r)∨(p∧q)(p \wedge r) \vee (p \wedge q)(p∧r)∨(p∧q)b.(q∧r)∨(p∧q)(q \wedge r) \vee (p \wedge q)(q∧r)∨(p∧q)c.(p∧r)∨(r∧q)(p \wedge r) \vee (r \wedge q)(p∧r)∨(r∧q)d.(p∧q)⇒(r∨q)(p \wedge q) \Rightarrow (r \vee q)(p∧q)⇒(r∨q)Login to continueOnly logged in users canattempt or see the solution.
