1.Let −π6<θ<−π12-\frac{\pi}{6} < \theta < -\frac{\pi}{12}−6π<θ<−12π. Suppose α1\alpha_1α1 and β1\beta_1β1 are the roots of x2−2xsecθ+1=0x^2 - 2x\sec\theta + 1 = 0x2−2xsecθ+1=0 and α2\alpha_2α2 and β2\beta_2β2 are the roots of x2+2xtanθ−1=0x^2 + 2x\tan\theta - 1 = 0x2+2xtanθ−1=0. If α1>β1\alpha_1 > \beta_1α1>β1 and α2>β2\alpha_2 > \beta_2α2>β2, then α1+β2\alpha_1 + \beta_2α1+β2 equalsa.2(secθ−tanθ)2(\sec\theta - \tan\theta)2(secθ−tanθ)b.2secθ2\sec\theta2secθc.−2tanθ-2\tan\theta−2tanθd.000Login to continueOnly logged in users canattempt or see the solution.
