1.What is the solution of dydx+2y=1\frac{dy}{dx} + 2y = 1dxdy+2y=1 satisfying y(0)=0y(0) = 0y(0)=0?a.y=1−e−2x2y = \frac{1 - e^{-2x}}{2}y=21−e−2xb.y=1+e−2x2y = \frac{1 + e^{-2x}}{2}y=21+e−2xc.y=1+exy = 1 + e^xy=1+exd.y=1+ex2y = \frac{1 + e^x}{2}y=21+exLogin to continueOnly logged in users canattempt or see the solution.
