1.If A=(cosθ−sinθsinθcosθ)A = \begin{pmatrix} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta \end{pmatrix}A=(cosθsinθ−sinθcosθ), then the matrix A50A^{50}A50 when θ=π12\theta = \dfrac{\pi}{12}θ=12π is equal to:a.(32−121232)\begin{pmatrix} \dfrac{\sqrt{3}}{2} & -\dfrac{1}{2} \\ \dfrac{1}{2} & \dfrac{\sqrt{3}}{2} \end{pmatrix}2321−2123b.(3212−1232)\begin{pmatrix} \dfrac{\sqrt{3}}{2} & \dfrac{1}{2} \\ -\dfrac{1}{2} & \dfrac{\sqrt{3}}{2} \end{pmatrix}23−212123c.(1001)\begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}(1001)d.(0−110)\begin{pmatrix} 0 & -1 \\ 1 & 0 \end{pmatrix}(01−10)Login to continueOnly logged in users canattempt or see the solution.
