1.If A⃗+B⃗=C⃗\vec{A} + \vec{B} = \vec{C}A+B=C and A=B+CA = B + CA=B+C (magnitudes), then the angle between A⃗\vec{A}A and B⃗\vec{B}B isa.000b.π4\dfrac{\pi}{4}4πc.π\piπd.π2\dfrac{\pi}{2}2πLogin to continueOnly logged in users canattempt or see the solution.