1.If ∣z1∣=∣z2∣=…=∣zn∣=1|z_1| = |z_2| = \ldots = |z_n| = 1∣z1∣=∣z2∣=…=∣zn∣=1, then the value of ∣z1+z2+…+zn∣−∣1z1+1z2+…+1zn∣|z_1 + z_2 + \ldots + z_n| - \left|\frac{1}{z_1} + \frac{1}{z_2} + \ldots + \frac{1}{z_n}\right|∣z1+z2+…+zn∣−z11+z21+…+zn1 isa.000b.111c.−1-1−1d.NoneLogin to continueOnly logged in users canattempt or see the solution.
