1.If the system of linear equationsx+y+z=5x + y + z = 5x+y+z=5x+2y+2z=6x + 2y + 2z = 6x+2y+2z=6x+3y+λz=μ(λ,μ∈R)x + 3y + \lambda z = \mu \quad (\lambda, \mu \in \mathbb{R})x+3y+λz=μ(λ,μ∈R)has infinitely many solutions, then the value of λ+μ\lambda + \muλ+μ is:a.777b.101010c.121212d.999Login to continueOnly logged in users canattempt or see the solution.