1.The potential energy for a force field F⃗\vec{F}F is given by U(x,y)=cos(x+y)U(x, y) = \cos(x + y)U(x,y)=cos(x+y). The force acting on a particle at position given by coordinates (0,π/4)(0, \pi/4)(0,π/4) isa.−(i^+j^)-(\hat{i} + \hat{j})−(i^+j^)b.12(i^+j^)\frac{1}{\sqrt{2}}(\hat{i} + \hat{j})21(i^+j^)c.12(i^+j^)\frac{1}{\sqrt{2}}(\hat{i} + \hat{j})21(i^+j^)d.(i^+j^)(\hat{i} + \hat{j})(i^+j^)Login to continueOnly logged in users canattempt or see the solution.