1.Let Sk=1+2+3+…+k=k(k+1)2S_k = 1 + 2 + 3 + \ldots + k = \dfrac{k(k+1)}{2}Sk=1+2+3+…+k=2k(k+1). If S12+S22+…+S102=2AS_1^2 + S_2^2 + \ldots + S_{10}^2 = 2AS12+S22+…+S102=2A, then AAA is equal to:a.301301301b.303303303c.156156156d.283283283Login to continueOnly logged in users canattempt or see the solution.
