1.Let a,ba, ba,b be the solutions of x2+px+1=0x^2 + px + 1 = 0x2+px+1=0 and c,dc, dc,d be the solutions of x2+qx+1=0x^2 + qx + 1 = 0x2+qx+1=0. If (a−c)(b−c)(a - c)(b - c)(a−c)(b−c) and (a+d)(b+d)(a + d)(b + d)(a+d)(b+d) are the solutions of x2+αx+β=0x^2 + \alpha x + \beta = 0x2+αx+β=0, then β\betaβ is equal toa.p+qp + qp+qb.p−qp - qp−qc.p2+q2p^2 + q^2p2+q2d.q2−p2q^2 - p^2q2−p2Login to continueOnly logged in users canattempt or see the solution.
