1.If 3+isinθ4−icosθ\dfrac{3 + i\sin\theta}{4 - i\cos\theta}4−icosθ3+isinθ, θ∈[0,2π]\theta \in [0, 2\pi]θ∈[0,2π], is a real number, then an argument of sinθ+icosθ\sin\theta + i\cos\thetasinθ+icosθ is:a.π−tan−1(13)\pi - \tan^{-1}\left(\dfrac{1}{3}\right)π−tan−1(31)b.π−tan−1(4)\pi - \tan^{-1}(4)π−tan−1(4)c.π−tan−1(14)\pi - \tan^{-1}\left(\dfrac{1}{4}\right)π−tan−1(41)d.tan−1(4)\tan^{-1}(4)tan−1(4)Login to continueOnly logged in users canattempt or see the solution.
