1.Cr2O72−+I−+H+⟶Cr3++I2+H2O\text{Cr}_2\text{O}_7^{2-} + \text{I}^- + \text{H}^+ \longrightarrow \text{Cr}^{3+} + \text{I}_2 + \text{H}_2\text{O}Cr2O72−+I−+H+⟶Cr3++I2+H2OThe equivalent weight of the reductant in the above equation is (At. wt. of Cr = 52, I = 127):a.26b.127c.63.5d.10.4Login to continueOnly logged in users canattempt or see the solution.