1.One mole of NaCl(s)\text{NaCl(s)}NaCl(s) absorbs 32.76 kJ at melting point; ΔS=30 J K−1mol−1\Delta S = 30\,\text{J K}^{-1}\text{mol}^{-1}ΔS=30J K−1mol−1. Melting point of NaCl?a.819 °Cb.1000 °Cc.1000 Kd.850 °CLogin to continueOnly logged in users canattempt or see the solution.
