1.Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated?a.2! 3! 4!2! \, 3! \, 4!2!3!4!b.(3!)3⋅(4!)(3!)^3 \cdot (4!)(3!)3⋅(4!)c.(3!)2⋅(4!)(3!)^2 \cdot (4!)(3!)2⋅(4!)d.3! (4!)33! \, (4!)^33!(4!)3Login to continueOnly logged in users canattempt or see the solution.