1.For α,β,z∈C\alpha, \beta, z \in \mathbb{C}α,β,z∈C and λ>1\lambda > 1λ>1, if λ2−1\sqrt{\lambda^2 - 1}λ2−1 is the radius of the circle ∣z−α∣2+∣z−β∣2=λ2|z - \alpha|^2 + |z - \beta|^2 = \lambda^2∣z−α∣2+∣z−β∣2=λ2, then ∣α−β∣|\alpha - \beta|∣α−β∣ is equal to:a.222\sqrt{2}22b.222c.232\sqrt{3}23d.2\sqrt{2}2Login to continueOnly logged in users canattempt or see the solution.
