1.In hydrogen atom, the de-Broglie wavelength of an electron in the second Bohr orbit is [Given that, Bohr radius, a0=52.9 pma_0 = 52.9\ pma0=52.9 pm]a.211.6 pmb.211.6π\piπ pmc.52.9π\piπ pmd.105.8 pmLogin to continueOnly logged in users canattempt or see the solution.
