1.The dissolution of Al(OH)3Al(OH)_3Al(OH)3 by a solution of NaOHNaOHNaOH results in the formation of:a.[Al(H2O)4(OH)2]+[Al(H_2O)_4(OH)_2]^+[Al(H2O)4(OH)2]+b.[Al(H2O)3(OH)3][Al(H_2O)_3(OH)_3][Al(H2O)3(OH)3]c.[Al(H2O)2(OH)4]−[Al(H_2O)_2(OH)_4]^-[Al(H2O)2(OH)4]−d.[Al(H2O)6(OH)3][Al(H_2O)_6(OH)_3][Al(H2O)6(OH)3]Login to continueOnly logged in users canattempt or see the solution.
