1.
A small object is thrown at an angle 4545^\circ to the horizontal with an initial velocity v0v_0. The velocity is averaged for first 2s\sqrt{2}\,\text{s} and the magnitude of average velocity comes out to be same as that of initial velocity, i.e. v0|v_0|. The magnitude v0|v_0| will be (take g=10m/s2g = 10\,\text{m/s}^2)