1.The vectors a⃗\vec{a}a and b⃗\vec{b}b are not perpendicular and c⃗\vec{c}c and d⃗\vec{d}d are two vectors satisfying b⃗×c⃗=b⃗×d⃗\vec{b} \times \vec{c} = \vec{b} \times \vec{d}b×c=b×d and a⃗⋅d⃗=0\vec{a} \cdot \vec{d} = 0a⋅d=0. Then the vector d⃗\vec{d}d is equal toa.c⃗+a⃗⋅c⃗a⃗⋅b⃗b⃗\vec{c} + \frac{\vec{a}\cdot\vec{c}}{\vec{a}\cdot\vec{b}} \vec{b}c+a⋅ba⋅cbb.b⃗+b⃗⋅c⃗a⃗⋅b⃗c⃗\vec{b} + \frac{\vec{b}\cdot\vec{c}}{\vec{a}\cdot\vec{b}} \vec{c}b+a⋅bb⋅ccc.c⃗−a⃗⋅c⃗a⃗⋅b⃗b⃗\vec{c} - \frac{\vec{a}\cdot\vec{c}}{\vec{a}\cdot\vec{b}} \vec{b}c−a⋅ba⋅cbd.b⃗−b⃗⋅c⃗a⃗⋅b⃗c⃗\vec{b} - \frac{\vec{b}\cdot\vec{c}}{\vec{a}\cdot\vec{b}} \vec{c}b−a⋅bb⋅ccLogin to continueOnly logged in users canattempt or see the solution.
