1.Locus of point whose chord of contact to x2/a2−y2/b2=1x^2/a^2-y^2/b^2=1x2/a2−y2/b2=1 subtends right angle at origina.x24a2−y24b2=1\frac{x^2}{4a^2}-\frac{y^2}{4b^2}=14a2x2−4b2y2=1b.x2a2−y2b2=x2a4+y2b4\frac{x^2}{a^2}-\frac{y^2}{b^2}=\frac{x^2}{a^4}+\frac{y^2}{b^4}a2x2−b2y2=a4x2+b4y2c.xa−yb=1a2+1b2\frac{x}{a}-\frac{y}{b}=\frac{1}{a^2}+\frac{1}{b^2}ax−by=a21+b21d.x2a4+y2b4=1a2−1b2\frac{x^2}{a^4}+\frac{y^2}{b^4}=\frac{1}{a^2}-\frac{1}{b^2}a4x2+b4y2=a21−b21Login to continueOnly logged in users canattempt or see the solution.