1.The curves x2a2+y24=4\frac{x^2}{a^2} + \frac{y^2}{4} = 4a2x2+4y2=4 and y3=16xy^3 = 16xy3=16x intersect each other orthogonally, then a2=a^2 =a2=a.222b.34\frac{3}{4}43c.12\frac{1}{2}21d.43\frac{4}{3}34Login to continueOnly logged in users canattempt or see the solution.
