1.Ship B is aaa km away steering perpendicular to line AB at speed vvv. Ship A alters course to pass in front of B with nearest approach ccc km, making angle α\alphaα with AB. If sinβ=c/a\sin\beta=c/asinβ=c/a, then A's speed isa.vcosβsin(α−β)\dfrac{v\cos\beta}{\sin(\alpha-\beta)}sin(α−β)vcosβb.vsinβcos(α−β)\dfrac{v\sin\beta}{\cos(\alpha-\beta)}cos(α−β)vsinβc.vsin(α−β)v\sin(\alpha-\beta)vsin(α−β)d.vsinα\dfrac{v}{\sin\alpha}sinαvLogin to continueOnly logged in users canattempt or see the solution.