1.If A=(2222)A = \begin{pmatrix} 2 & 2 \\ 2 & 2 \end{pmatrix}A=(2222) and I=I2I = I_2I=I2 is the 2×22 \times 22×2 identity matrix, then A2−4AA^2 - 4AA2−4A is equal to:a.A−4IA - 4IA−4Ib.6I−A6I - A6I−Ac.A−6IA - 6IA−6Id.4I−A4I - A4I−ALogin to continueOnly logged in users canattempt or see the solution.
