1.A particle moves along the xxx-axis according to x=A[1+sinωt]x = A[1 + \sin\omega t]x=A[1+sinωt]. What distance does it travel between t=0t = 0t=0 and t=2.5πωt = \dfrac{2.5\pi}{\omega}t=ω2.5π?a.4A4A4Ab.6A6A6Ac.5A5A5Ad.NoneLogin to continueOnly logged in users canattempt or see the solution.