1.An electron is accelerated through a potential difference of 45.545.545.5 V. The velocity acquired by it is (in ms−1^{-1}−1)a.10610^6106b.zeroc.4×1064 \times 10^64×106d.4×1044 \times 10^44×104Login to continueOnly logged in users canattempt or see the solution.
