1.Let α\alphaα and β\betaβ be the roots of the equation x2+x+1=0x^2 + x + 1 = 0x2+x+1=0. Then for y≠0y \neq 0y=0 in R\mathbb{R}R, ∣y+1αβαy+β1β1y+α∣\begin{vmatrix} y+1 & \alpha & \beta \\ \alpha & y+\beta & 1 \\ \beta & 1 & y+\alpha \end{vmatrix}y+1αβαy+β1β1y+α is equal to:a.y3y^3y3b.y(y2−1)y(y^2 - 1)y(y2−1)c.y3−1y^3 - 1y3−1d.y(y2−3)y(y^2 - 3)y(y2−3)Login to continueOnly logged in users canattempt or see the solution.
