1.A big water drop is divided into 8 equal droplets. ΔPs\Delta P_sΔPs and ΔPB\Delta P_BΔPB be the excess pressure inside a smaller and bigger drop respectively. The relation between ΔPs\Delta P_sΔPs and ΔPB\Delta P_BΔPB isa.ΔPB=ΔPs\Delta P_B = \Delta P_sΔPB=ΔPsb.ΔPB=12ΔPs\Delta P_B = \frac{1}{2} \Delta P_sΔPB=21ΔPsc.ΔPB=14ΔPs\Delta P_B = \frac{1}{4} \Delta P_sΔPB=41ΔPsd.ΔPB=2ΔPs\Delta P_B = 2 \Delta P_sΔPB=2ΔPsLogin to continueOnly logged in users canattempt or see the solution.