1.A force F⃗=(5i^+3j^+2k^)\vec{F} = (5\hat{i} + 3\hat{j} + 2\hat{k})F=(5i^+3j^+2k^) N is applied over a particle which displaces it from its origin to the point r⃗=(2i^−j^)\vec{r} = (2\hat{i} - \hat{j})r=(2i^−j^) m. The work done on the particle in joules isa.−7-7−7b.+7+7+7c.+10+10+10d.+13+13+13Login to continueOnly logged in users canattempt or see the solution.
