1.A body of mass 3 kg is under a constant force which causes a displacement sss in metres in it, given by the relation s=13t2s = \frac13 t^2s=31t2, where ttt is in seconds. Work done by the force in 2 seconds is:a.195\frac{19}{5}519 Jb.519\frac{5}{19}195 Jc.38\frac{3}{8}83 Jd.83\frac{8}{3}38 JLogin to continueOnly logged in users canattempt or see the solution.