1.f(x)=tan{π[x−π/2]}2+[x]2f(x)=\frac{\tan\{\pi[x-\pi/2]\}}{2+[x]^2}f(x)=2+[x]2tan{π[x−π/2]} isa.cont for all xxxb.disc at x=π/2x=\pi/2x=π/2c.not diff for some xxxd.disc at x=−2x=-2x=−2Login to continueOnly logged in users canattempt or see the solution.
