1.The area (in sq. units) of the region lying in the first quadrant and enclosed by the XXX-axis, the straight line x−3y=0x - \sqrt{3}y = 0x−3y=0 and the circle x2+y2=4x^2 + y^2 = 4x2+y2=4, isa.π3\frac{\pi}{3}3πb.2π3\frac{2\pi}{3}32πc.π23\frac{\pi}{2\sqrt{3}}23πd.2π32\frac{2\pi}{3\sqrt{2}}322πLogin to continueOnly logged in users canattempt or see the solution.
