1.(6,0)(6, 0)(6,0), (0,6)(0, 6)(0,6) and (7,7)(7, 7)(7,7) are the vertices of a triangle. The circle inscribed in the triangle has the equationa.x2+y2−9x+9y+36=0x^2 + y^2 - 9x + 9y + 36 = 0x2+y2−9x+9y+36=0b.x2+y2−9x−9y+36=0x^2 + y^2 - 9x - 9y + 36 = 0x2+y2−9x−9y+36=0c.x2+y2+9x−9y+36=0x^2 + y^2 + 9x - 9y + 36 = 0x2+y2+9x−9y+36=0d.x2+y2−9x−9y−36=0x^2 + y^2 - 9x - 9y - 36 = 0x2+y2−9x−9y−36=0Login to continueOnly logged in users canattempt or see the solution.
