1.Let f(x)=∣a−10axa−1ax2axa∣f(x)=\begin{vmatrix} a & -1 & 0 \\ ax & a & -1 \\ ax^{2} & ax & a \end{vmatrix}f(x)=aaxax2−1aax0−1a, a∈Ra\in\mathbb{R}a∈R. Then the sum of the squares of all the values of aaa for which 2f′(10)−f′(5)+100=02f'(10)-f'(5)+100=02f′(10)−f′(5)+100=0 is:a.117117117b.106106106c.125125125d.136136136Login to continueOnly logged in users canattempt or see the solution.
