1.Let the number (22)2022+(2022)22(22)^{2022} + (2022)^{22}(22)2022+(2022)22 leave the remainder α\alphaα when divided by 3 and β\betaβ when divided by 7. Then α2+β2\alpha^2 + \beta^2α2+β2 is equal toa.111b.888c.666d.444Login to continueOnly logged in users canattempt or see the solution.
