1.If f(x)={logxx−1,x≠1k,x=1f(x)=\begin{cases}\frac{\log x}{x-1},&x\ne1\\k,&x=1\end{cases}f(x)={x−1logx,k,x=1x=1 continuous at 111, find kkka.0b.-1c.1d.eeeLogin to continueOnly logged in users canattempt or see the solution.
