1.If z1=1−2iz_1 = 1 - 2iz1=1−2i, z2=1+iz_2 = 1 + iz2=1+i and z3=3+4iz_3 = 3 + 4iz3=3+4i, then (1z1+2z2)z3z2=\left(\frac{1}{z_1} + \frac{2}{z_2}\right) \frac{z_3}{z_2} =(z11+z22)z2z3=a.7/2\sqrt{7}/27/2b.151515c.7\sqrt{7}7d.15/215/215/2Login to continueOnly logged in users canattempt or see the solution.
