1.The area of the region bounded by the parabola y=x2−4x+5y = x^2 - 4x + 5y=x2−4x+5 and the straight line y=x+1y = x + 1y=x+1 isa.12\frac{1}{2}21b.222c.333d.92\frac{9}{2}29Login to continueOnly logged in users canattempt or see the solution.
