1.Eccentricity of x2/a2−y2/b2=1x^2/a^2 - y^2/b^2 = 1x2/a2−y2/b2=1 is reciprocal of that of ellipse x2+9y2=9x^2+9y^2=9x2+9y2=9. Then a2:b2a^2:b^2a2:b2 isa.8:18:18:1b.1:81:81:8c.9:19:19:1d.1:91:91:9Login to continueOnly logged in users canattempt or see the solution.