1.Under which one of the following conditions does the system of equations{kx+y+z=k−1x+ky+z=k−1x+y+kz=k−1\begin{cases} kx + y + z = k - 1 \\ x + ky + z = k - 1 \\ x + y + kz = k - 1 \end{cases}⎩⎨⎧kx+y+z=k−1x+ky+z=k−1x+y+kz=k−1have a unique solution?a.k=1k = 1k=1b.k≠−2k \ne -2k=−2c.k=1k = 1k=1 or k=−2k = -2k=−2d.k=−2k = -2k=−2Login to continueOnly logged in users canattempt or see the solution.
