1.∫cos(logex) dx\int \cos(\log_e x)\,dx∫cos(logex)dx is equal to (where CCC is constant)a.x[cos(logx)−sin(logx)]+Cx[\cos(\log x)-\sin(\log x)]+Cx[cos(logx)−sin(logx)]+Cb.x2[sin(logx)−cos(logx)]+C\frac{x}{2}[\sin(\log x)-\cos(\log x)]+C2x[sin(logx)−cos(logx)]+Cc.x2[sin(logx)+cos(logx)]+C\frac{x}{2}[\sin(\log x)+\cos(\log x)]+C2x[sin(logx)+cos(logx)]+Cd.x[cos(logx)+sin(logx)]+Cx[\cos(\log x)+\sin(\log x)]+Cx[cos(logx)+sin(logx)]+CLogin to continueOnly logged in users canattempt or see the solution.
