1.If the equation sin4x−(k+2)sin2x−(k+3)=0\sin^4 x - (k + 2)\sin^2 x - (k + 3) = 0sin4x−(k+2)sin2x−(k+3)=0 has a solution then kkk must lie in the intervala.(−4,−2)(-4, -2)(−4,−2)b.[−3,2)[-3, 2)[−3,2)c.(−4,−3)(-4, -3)(−4,−3)d.[−3,−2][-3, -2][−3,−2]Login to continueOnly logged in users canattempt or see the solution.
