1.If the latus rectum of an ellipse subtends a right angle at the centre, then the eccentricity of that ellipse isa.5+14\frac{\sqrt{5}+1}{4}45+1b.5−12\frac{\sqrt{5}-1}{2}25−1c.10−255\frac{\sqrt{10-2\sqrt{5}}}{5}510−25d.10+255\frac{\sqrt{10+2\sqrt{5}}}{5}510+25Login to continueOnly logged in users canattempt or see the solution.
