1.If α=limx→0x⋅2x−x1−cosx\alpha=\displaystyle\lim_{x\to0}\frac{x\cdot2^x-x}{1-\cos x}α=x→0lim1−cosxx⋅2x−x and β=limx→0x⋅2x−x1+x2−1−x2\beta=\displaystyle\lim_{x\to0}\frac{x\cdot2^x-x}{\sqrt{1+x^2}-\sqrt{1-x^2}}β=x→0lim1+x2−1−x2x⋅2x−x, thena.α=β\alpha=\betaα=βb.α=2β\alpha=2\betaα=2βc.α=β/2\alpha=\beta/2α=β/2d.α=3β\alpha=3\betaα=3βLogin to continueOnly logged in users canattempt or see the solution.
