1.Let A=(cosθsinθ01)A = \begin{pmatrix} \cos\theta & \sin\theta \\ 0 & 1 \end{pmatrix}A=(cosθ0sinθ1) and P=(cosθsinθ−sinθcosθ)P = \begin{pmatrix} \cos\theta & \sin\theta \\ -\sin\theta & \cos\theta \end{pmatrix}P=(cosθ−sinθsinθcosθ). If B=PAPTB = PAP^{T}B=PAPT and C=PTB10PC = P^{T}B^{10}PC=PTB10P, and the sum of the diagonal elements of CCC is mn\dfrac{m}{n}nm with gcd(m,n)=1\gcd(m, n) = 1gcd(m,n)=1, then m+nm + nm+n is:a.127127127b.258258258c.656565d.204920492049Login to continueOnly logged in users canattempt or see the solution.
