1.A man who is running has half the kinetic energy of a boy of half his mass. The man speeds up by 1 m/s1\,\text{m/s}1m/s and then has the same kinetic energy as the boy. The original speed of the man wasa.2 m/s\sqrt{2}\,\text{m/s}2m/sb.(2−1) m/s(\sqrt{2} - 1)\,\text{m/s}(2−1)m/sc.12 m/s\dfrac{1}{\sqrt{2}}\,\text{m/s}21m/sd.(2+1) m/s(\sqrt{2} + 1)\,\text{m/s}(2+1)m/sLogin to continueOnly logged in users canattempt or see the solution.