1.Let a⃗=2i^−2j^+k^\vec{a} = 2\hat{i} - 2\hat{j} + \hat{k}a=2i^−2j^+k^, b⃗=−j^+k^\vec{b} = -\hat{j} + \hat{k}b=−j^+k^. If c⃗\vec{c}c is a vector such that a⃗⋅c⃗=∣c⃗∣\vec{a} \cdot \vec{c} = |\vec{c}|a⋅c=∣c∣, ∣c⃗−a⃗∣=22|\vec{c} - \vec{a}| = 2\sqrt{2}∣c−a∣=22 and the angle between a⃗×b⃗\vec{a} \times \vec{b}a×b and c⃗\vec{c}c is π3\frac{\pi}{3}3π, then ∣(a⃗×b⃗)×c⃗∣=|(\vec{a} \times \vec{b}) \times \vec{c}| =∣(a×b)×c∣=a.333\sqrt{3}33b.32\frac{3}{2}23c.332\frac{3\sqrt{3}}{2}233d.000Login to continueOnly logged in users canattempt or see the solution.