1.If Z1,Z2,Z3Z_1, Z_2, Z_3Z1,Z2,Z3 are 3 distinct complex numbers such that 3Z2−Z3=4Z3−Z1=5Z1−Z2\frac{3}{Z_2 - Z_3} = \frac{4}{Z_3 - Z_1} = \frac{5}{Z_1 - Z_2}Z2−Z33=Z3−Z14=Z1−Z25, then the value of 9Z2−Z3+16Z3−Z1+25Z1−Z2\frac{9}{Z_2 - Z_3} + \frac{16}{Z_3 - Z_1} + \frac{25}{Z_1 - Z_2}Z2−Z39+Z3−Z116+Z1−Z225 equalsa.000b.333c.444d.555Login to continueOnly logged in users canattempt or see the solution.
