1.The number of ordered pairs (r,k)(r, k)(r,k) for which 6⋅(35r)=(k2−3)⋅(36r+1)6 \cdot \binom{35}{r} = (k^2 - 3) \cdot \binom{36}{r+1}6⋅(r35)=(k2−3)⋅(r+136), where kkk is an integer, isa.333b.222c.666d.444Login to continueOnly logged in users canattempt or see the solution.
